SIMPLE INTEREST AND ALL ITS ELEMENTS

Simple Interest = (PXRXT)/100 If , principal money is ₹2000, interest rate per annum = 10% & time is 3 years ,find SI and Amount (A). We know that, SI = PRT/100 So, SI = 2000×10×3/100 = ₹600 Since, Amount (A) = P+ SI = ₹2000+₹600 = ₹2600 Now , If SI = PRT/100 Then, P = SIX100/(TR) Then, R = SIX100/(PT Then, T = SIX100/PR If, A = P +SI Or, A= P+ PRT/100 Or, A = P(1+ RT/100) Or, A = P( 100+RT)/100 Now, if A = P(100+RT)/100 Verification : A = 2000(100+10x3/100 A = 2000x(130)/100 = 20x130 Therefore, Amount = ₹2600 Then, PX(100+RT)/100) = A Or, P = AX100/(100+RT) Verification: P= 2600x100/(100+10x3) P= 2600x100/130 P= 2000 Therefore, Principal = ₹ 2000 if A = P(100+RT)/100 Then, P(100+RT) /100= A or P= Ax100/(100+RT) Or, (100+RT) = Ax100/P Or, RT = (Ax100/P)-100 Or, R= {(AX100/P)-100}/T Verification: R = {(2600x100/2000-100}/3 Or, R = (2600/20-100)/3 Or, R = (130-100)/3 Or, R = 30/3 Therefore , R = Rate of interest = 10% Since RT = {(AX100/P)-100} Then, T = {(Ax100/P)-100}/R Verification = Since , T = {(AX100/P)-100}/R Putting respective values in the above formula T = {(2600x100/2000)-100}/10 Or, T = (2600/20-100)/10 Or, T = (130-100)/10 Or, T = 30/10 Therefore, T = TIME = 3 YEARS call or chat on 9333124957